2.4 字符串匹配和搜索
问题
解决方案
>>> datepat = re.compile(r'(\d+)/(\d+)/(\d+)')
>>> m = datepat.match('11/27/2012')
>>> m
<_sre.SRE_Match object at 0x1005d2750>
>>> # Extract the contents of each group
>>> m.group(0)
'11/27/2012'
>>> m.group(1)
'11'
>>> m.group(2)
'27'
>>> m.group(3)
'2012'
>>> m.groups()
('11', '27', '2012')
>>> month, day, year = m.groups()讨论
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