9.16 args和*kwargs的强制参数签名
问题
解决方案
>>> from inspect import Signature, Parameter
>>> # Make a signature for a func(x, y=42, *, z=None)
>>> parms = [ Parameter('x', Parameter.POSITIONAL_OR_KEYWORD),
... Parameter('y', Parameter.POSITIONAL_OR_KEYWORD, default=42),
... Parameter('z', Parameter.KEYWORD_ONLY, default=None) ]
>>> sig = Signature(parms)
>>> print(sig)
(x, y=42, *, z=None)>>> def func(*args, **kwargs):
... bound_values = sig.bind(*args, **kwargs)
... for name, value in bound_values.arguments.items():
... print(name,value)
...
>>> # Try various examples
>>> func(1, 2, z=3)
x 1
y 2
z 3
>>> func(1)
x 1
>>> func(1, z=3)
x 1
z 3
>>> func(y=2, x=1)
x 1
y 2
>>> func(1, 2, 3, 4)
Traceback (most recent call last):
...
File "/usr/local/lib/python3.3/inspect.py", line 1972, in _bind
raise TypeError('too many positional arguments')
TypeError: too many positional arguments
>>> func(y=2)
Traceback (most recent call last):
...
File "/usr/local/lib/python3.3/inspect.py", line 1961, in _bind
raise TypeError(msg) from None
TypeError: 'x' parameter lacking default value
>>> func(1, y=2, x=3)
Traceback (most recent call last):
...
File "/usr/local/lib/python3.3/inspect.py", line 1985, in _bind
'{arg!r}'.format(arg=param.name))
TypeError: multiple values for argument 'x'讨论
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